perfect sensitivity v2
evil claims...
good i am not everyone . I have sensefull usage for my office since i also work at home sometimes.
It seems that I have had already the best sens' : 1.
i am trying to make same ruler maps for your first formula.... and seemed, it brings visually the same. So I probably failed with my researches. I update this post soon with a new pak
EDIT: try these maps with the original formula (from first posted qsens_v1.0.ods, which I re-post here):
PP360 = pi * width / tan (cg_fov/2)
m_yaw = 360 * tan(cg_fov/2) / ( pi * width )
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mapname cgfov60: cg_fov = 60, m_yaw = 0.5169 ()
mapname cgfov90: cg_fov = 90, m_yaw = 0.8952 ()
mapname cgfov105: cg_fov = 105, m_yaw = 1.1667 ()
mapname cgfov120: cg_fov = 120, m_yaw = 1.5506 ()
Now it looks even better...
I think it demonstrates that pixel step is almost irrelevant to 3D graphics... However trying to find a strict math proof, I could not get it for my formula but for yours. My formula makes the pixel some wider - 1.05-1.20 times - thats why the result seemed /and felt/ fine.
BTW how did you measure PP360 for cgfov120?
So your formula is correct ( and cgfov maps too ).
Ruler was not a way to prove, it was a rendition of the formula and used to check yaw.
EDIT: the question is: could you feel something wrong being stuck with my formula? Perhaps the perfect sensitivity is something else than 1px VA, something not dependant of pixels and resolutions...
there was a point to make rulers, because they are supposed to be drawn pixelwise and thus demonstrate pixelwise turns (note that the ruler pins in cgfov maps have exactly 2px onscreen width and steps are exactly 8 px)
calculator had a update see first post
I am addicted to life.